Re: Numerical expression

*To*: mathgroup at smc.vnet.net*Subject*: [mg128798] Re: Numerical expression*From*: Bob Hanlon <hanlonr357 at gmail.com>*Date*: Tue, 27 Nov 2012 03:31:09 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net*References*: <20121126042617.44760687B@smc.vnet.net>

This does not appear to equal one. Assuming that the exponents are intended to be rational and that the parentheses are balanced as follows expr = ((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/3))/(3)^(1/2) (2*(9*Sqrt[3] + 4*Sqrt[23])^(1/3))/ Sqrt[3] expr // FullSimplify 1 + Sqrt[23/3] expr // N 3.76887 Bob Hanlon On Sun, Nov 25, 2012 at 11:26 PM, Massimo <linusx++ at mail.com> wrote: > How could I handle in Mathematica this expression? > > ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2) > > With a lot of trouble I have found out that is equal 1, > but how to get it with Mathematica? > > Thanks very much. > > > > __________ Informazioni da ESET Smart Security, versione del database del= le firme digitali 7729 (20121125) __________ > > Il messaggio =E8 stato controllato da ESET Smart Security. > > www.nod32.it > > > > >

**References**:**Numerical expression***From:*"Massimo" <linusx++@mail.com>