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Re: Fibonacci integers


If you rewrite 'm' as a matrix, you do get True:

m={{1,1},{1,2}};
n=3;
MatrixPower[m,n]==
{{Fibonacci[2 n-1],Fibonacci[2 n]},
{Fibonacci[2 n],Fibonacci[2 n+1]}}


On Sat, Feb 2, 2013 at 11:48 PM, Andre Hautot <ahautot at ulg.ac.be> wrote:
>
> Hi, let
> m={1,1},{1,2}
> and n be an  integer
>
> MatrixPower[m, n]  = = {{Fibonacci[2 n - 1], Fibonacci[2 n]},
> {Fibonacci[2 n], Fibonacci[2 n + 1]}}
>
> should be indentically True
>
> I have tried FunctionExpand and FullSimplify without success, any idea ?
> Thanks in advance,
>
> Andre
>



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