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Re: A nonconventional ListContourPlot

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  • Subject: [mg129914] Re: A nonconventional ListContourPlot
  • From: "djmpark" <djmpark at comcast.net>
  • Date: Mon, 25 Feb 2013 02:22:38 -0500 (EST)
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ContourPlot[Sin[x + y^2], {x, -2, 2}, {y, -1, 1},
 ColorFunction -> ColorData["DarkRainbow"]] 

??

Rather, why do you want to sample at your strange set of x,y values? Is the
z expression just a stand-in for actual measure values? You might try
Interpolation with InterpolatingOrder -> 1, but the results in this case do
not seem promising.


David Park
djmpark at comcast.net 
http://home.comcast.net/~djmpark/index.html 




From: Luiz Melo [mailto:lmelo at ufsj.edu.br] 


Good day,

x[a_,b_] = a*b;
y[a_,b_] = Cos[a^2 + b];
z[a_,b_] = Sin[a + b^2];

data = Table[{x[i,j], y[i,j], z[i,j]}, {j, -1, 1, 0.1}, {i, -2, 2, 0.1}];

For the table above, is it possible to see a ListContourPlot of the z
component as a function of x and y (the values of x and y on the horizontal
and vertical axes, respectively)?

Thank you in advance
Luiz Melo




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