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Re: Problem with DateListPlot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg129459] Re: Problem with DateListPlot
  • From: "Gower, Luke" <lgower at kpmg.com.au>
  • Date: Tue, 15 Jan 2013 00:37:20 -0500 (EST)
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  • References: <20130115042924.D66E468E0@smc.vnet.net> <CAEtRDSfviPM6dLCK=F1Xfv9GE8yo8Uyws00fYU2BsoyXjpWJyA@mail.gmail.com>

You are a champion, Bob. Thanks indeed. Luke.

-----Original Message-----
From: Bob Hanlon [mailto:hanlonr357 at gmail.com]
Sent: Tuesday, 15 January 2013 4:28 PM
To: Gower, Luke
Cc: mathgroup at smc.vnet.net
Subject: [mg129459] Re: [mg129447] Problem with DateListPlot

Use Sequence

DateListPlot[{x, Sequence @@ z},
 Joined -> Join[{False}, Table[True, {Length[z]}]],  PlotRange -> {0,
12}]


Bob Hanlon


On Mon, Jan 14, 2013 at 11:29 PM, Luke Gower <lgower at kpmg.com.au> wrote:
> Hi folks. This should be really easy, but it is eluding me. Consider
the following points and graphic.
>
> =
x=List[DateString[DatePlus[#],{"Day","MonthNameShort","YearShort"}],#]
> &/@Range[10]; y=ReplacePart[Take[x,{2,-1,2}],{_,-1}->10];
> DateListPlot[{x,y},PlotRange->{0,12}]
>
> The plot consists of one diagonal and one horizontal set of points. My
problem is that, in the graphic, I would like to join pairs: y[[1]] and
y[[2]]; y[[3]] and y[[4]]. An obvious (if ugly) hack is as follows:
>
> z=Partition[y,2];
> DateListPlot[{x, z[[1]], z[[2]]}, Joined -> Join[{False}, Table[True,
> {Length[z]}]], PlotRange -> {0, 12}]
>
> Unfortunately, in the real version of this problem, the length of y is
variable, so I need a solution in terms of y, which does not involve
manually entering parts of z.
>
> And that is where I get stuck.
>
> Any suggestions?
> Many thanks indeed.
> Luke
>



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