List manipulation question - 2013

*To*: mathgroup at smc.vnet.net*Subject*: [mg129618] List manipulation question - 2013*From*: Lea Rebanks <lrebanks at gmail.com>*Date*: Wed, 30 Jan 2013 04:26:53 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net

Dear All, I have the follow problem with the combination of a few lists. I shall outline the problem or what I am trying to do. I know that to solve this problem requires a number of processes, but I am not sure how to setup the coding to achieve my desired result. Please could someone show me the coding for this problem. The problem:- 1 - I have a list1 created from 24+(15*n1) All n1 are integers 1,2,3,4.....to a large number of integers. 2 - I want to divide the list1 by 24 and create another list2 with only the integer results in list2. Table[24 + 15*i, {i, 100}]/24 ... so that integer results in list2 = { 144, 264, 384, 504, 624, 744, 864, 984, 1104 } 3 - I have another list3 created from 12+(3*n2) All n2 are integers 1,2,3,4.....to a large number of integers. 4 - With list3 I want to find :- (i) The integer number of n2 that either equates 12+(3*n2) = 144 or the next FIRST available number in list2 that meets this equality. then also (ii)The integer number(s) of n2 that equates 12+(3*n2) = 24+(15*n1) after the first equal value for say 6 repetitions. then also (iii)The integer number(s) of n1 that equates 12+(3*n2) = 24+(15*n1) after the first equal value for say 6 repetitions. The above example is quite simple, but I am hoping to setup the coding to work with other integer values instead of 3 & 15 which will present more of a challenge. Any help or advice greatly appreciated. Best regards, Lea...

**Follow-Ups**:**Re: List manipulation question - 2013***From:*Bob Hanlon <hanlonr357@gmail.com>

**Re: List manipulation question - 2013***From:*Lea Rebanks <lrebanks@gmail.com>

**Re: List manipulation question - 2013***From:*Bob Hanlon <hanlonr357@gmail.com>

**Re: List manipulation question - 2013***From:*christopher arthur <chris.arthur1@gmail.com>