Re: Russian Peasant Multiplication / was question on how to do this

*To*: mathgroup at smc.vnet.net*Subject*: [mg131386] Re: Russian Peasant Multiplication / was question on how to do this*From*: d.a.paxton at gmail.com*Date*: Tue, 2 Jul 2013 00:49:22 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-outx@smc.vnet.net*Delivered-to*: mathgroup-newsendx@smc.vnet.net*References*: <kqm6u7$hp5$1@smc.vnet.net>

On Saturday, June 29, 2013 2:47:03 AM UTC-6, Richard Fateman wrote: > Dave -- > > 1. You should try to come up with a useful subject line > > in the future. > > 2. It is called Russian Peasant Multiplication (which you may > > find on Google). > > 3. There is no reason to believe that a procedural algorithm > > has a formula, but in this case I think the inverse is known > > as division :) Bob, Thanks on that. I see the use of the floor function. This whole idea is trivial when one can use that. What I am trying to do is basically do the floor function as a linear equation. This is useful for pulling numbers apart. Like a number 13. How does one algebraically make it 1 and 3 or 10 and 3. Either.

**Follow-Ups**:**Re: Russian Peasant Multiplication / was question on***From:*James Stein <mathgroup@stein.org>