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Re: inconsistent refinement behavior


On 7/12/13 at 2:49 AM, akrasnov at cory.eecs.berkeley.edu (Alex Krasnov)
wrote:

>Firstly, x==0 also implicitly assumes that x is in Reals, since 0 is
>in Reals, as the following examples demonstrate:

>In:    Assuming[x==0, Refine[Element[x, Reals]]] Out:  True

>In:    Assuming[{Element[x, Reals], x==0}, Refine[Infinity/x]]
>Out:   ComplexInfinity

No so. Consider

In[1]:= Assuming[x == 0, Refine[Element[x, Complexes]]]

Out[1]= True




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