       Re: Exploiting relationships in manipulations: example

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• Subject: [mg131342] Re: Exploiting relationships in manipulations: example
• From: Bob Hanlon <hanlonr357 at gmail.com>
• Date: Sat, 29 Jun 2013 04:58:31 -0400 (EDT)
• Approved: Steven M. Christensen <steve@smc.vnet.net>, Moderator
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• Delivered-to: l-mathgroup@wolfram.com
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• Newsgroups: comp.soft-sys.math.mathematica
• References: <20130628081233.8C1D769C6@smc.vnet.net>

```tel = {2/15 Sqrt[=F0] (5 ff + 2 Sqrt ff),
-I Sqrt[(2 =F0)/15] (ff[-1] + ff),
1/15 Sqrt[=F0] (10 ff - Sqrt*
(Sqrt ff[-2] + 2 ff + Sqrt ff)),
Sqrt[(2 =F0)/15] (ff[-1] - ff),
-I Sqrt[(2 =F0)/15] (ff[-2] - ff),
1/15 Sqrt[=F0] (10 ff + Sqrt*
(Sqrt ff[-2] - 2 ff + Sqrt ff))};

FullSimplify[tel /. Cases[tel,
ff[l_][m_?Negative] :>
(ff[l][m] :> Conjugate[ff[l][-m]]*(-1)^m),
Infinity] // Union] /. (Re[x_] - x_) :> -Im[x]

{(2/15)*Sqrt[Pi]*(5*ff +
2*Sqrt*ff),
-2*Sqrt[(2*Pi)/15]*Re[ff],
-2*I*Sqrt[(2*Pi)/15]*Im[ff],
2*I*Sqrt[(2*Pi)/15]*Im[ff],
(2/15)*Sqrt[Pi]*
(Sqrt*Re[ff] +
5*ff - Sqrt*ff),
(-(2/15))*Sqrt[Pi]*
(Sqrt*Re[ff] -
5*ff + Sqrt*ff)}

Bob Hanlon

On Fri, Jun 28, 2013 at 1:30 PM, Sune Jespersen <sunenj at gmail.com> wrote:

> Thanks. I meant  ff[l][m] == Conjugate[ff[l][-m]]*(-1)^m). It seems your
> solution in this case produces an output fully identical (unchanged) to tel.
> For example, I wanted the 2nd element of tel
> I Sqrt[(2 =F0)/15] (ff[-1] + ff)
> to become
> -2 Sqrt[(2 =F0)/15] Im(ff).
>
> Sune
>
> On 28 Jun, 2013, at 17:42 , Bob Hanlon <hanlonr357 at gmail.com> wrote:
>
> tel = {2/15 Sqrt[
>      =F0] (5 ff + 2 Sqrt ff), -I Sqrt[(2 =F0)/15] (ff[-1] +
>       ff),
>    1/15 Sqrt[
>      =F0] (10 ff -
>       Sqrt (Sqrt ff[-2] + 2 ff + Sqrt ff)),
>    Sqrt[(2 =F0)/15] (ff[-1] - ff), -I Sqrt[(2 =F0)/15] (ff[-2] -
>       ff),
>    1/15 Sqrt[
>      =F0] (10 ff +
>       Sqrt (Sqrt ff[-2] - 2 ff + Sqrt ff))};
>
> In your text you state ff[l][m] == ff[l][-m] (-1)^m
>
> Simplify[tel,
>  Union[Cases[tel, ff[_][_], Infinity]] /.
>   ff[l_][m_] -> (ff[l][m] == ff[l][-m] (-1)^m)]
>
> {(2/15)*Sqrt[Pi]*(5*ff +
>         2*Sqrt*ff), 0, (2/15)*Sqrt[Pi]*
>      (5*ff - Sqrt*(ff +
>              Sqrt*ff)), -2*Sqrt[(2*Pi)/15]*
>      ff, 0, (2/15)*Sqrt[Pi]*
>      (5*ff - Sqrt*ff +
>         Sqrt*ff)}
>
> However, in your code you use ff[l][m] == Conjugate[ff[l][-m]]*(-1)^m)
>
> Simplify[tel,
>  Union[Cases[tel, ff[_][_], Infinity]] /.
>   ff[l_][m_] -> (ff[l][m] == Conjugate[ff[l][-m]]*(-1)^m)]
>
> {(2/15)*Sqrt[Pi]*(5*ff +
>         2*Sqrt*ff), (-I)*Sqrt[(2*Pi)/15]*
>      (ff[-1] + ff), (1/15)*Sqrt[Pi]*
>      (10*ff - Sqrt*(Sqrt*ff[-2] +
>              2*ff + Sqrt*ff)),
>    Sqrt[(2*Pi)/15]*(ff[-1] - ff),
>    (-I)*Sqrt[(2*Pi)/15]*(ff[-2] - ff),
>    (1/15)*Sqrt[Pi]*(10*ff +
>         Sqrt*(Sqrt*ff[-2] - 2*ff +
>              Sqrt*ff))}
>
> % === tel
>
> True
>
>
> Bob Hanlon
>
>
>
> On Fri, Jun 28, 2013 at 4:12 AM, Sune <sunenj at gmail.com> wrote:
>
>> Hey all.
>>
>> I'm trying to get Mathematica to simplify a list of expressions involving
>> complex symbolic variables with certain relations among them, and to take
>> advantage of these relations while simplifying.
>>
>> To be more concrete, I could have a list such as
>>
>> tel={2/15 Sqrt[\[Pi]] (5 ff+2 Sqrt ff),-I Sqrt[(2
>> \[Pi])/15] (ff[-1]+ff),1/15 Sqrt[\[Pi]] (10 ff-Sqrt
>> (Sqrt ff[-2]+2 ff+Sqrt ff)),Sqrt[(2 \[Pi])/15]
>> (ff[-1]-ff),-I Sqrt[(2 \[Pi])/15] (ff[-2]-ff),1/15
>> Sqrt[\[Pi]] (10 ff+Sqrt (Sqrt ff[-2]-2 ff+Sqrt
>> ff))}
>>
>> However, there's a conjugate symmetry among the variables ff[l][m] that
>> would enable a simpler looking expression. Specifically, ff[l][m]=ff[l][-m]
>> (-1)^m, and I would like to have Mathematica take advantage of that and
>> reduce expressions such as
>>
>> I Sqrt[(2 \[Pi])/15] (ff[-1]+ff)
>>
>> to
>>
>> -Sqrt[(2 \[Pi])/15] 2*Im(ff)
>>
>>
>> I've tried various combinations of ComplexExpand and FullSimplify;
>>
>> ComplexExpand[
>>  FullSimplify[tel,
>>   And @@ Flatten[
>>     Table[ff[l][m] == Conjugate[ff[l][-m]]*(-1)^m, {l, 0, 4, 2}, {m,
>>       0, l}]]], Flatten[Table[ff[l][m] , {l, 2, 4, 2}, {m, -l, l}]]]
>>
>> (And also version with the two outermost commands interchanged)
>>  but it doesn't do what I want. Of course, it may be that the rules for
>> simplify are such that my sought expression is not considered a simpler
>> version of the same expression. Could that be the case? Otherwise, I'd
>> appreciate any suggestions on how to implement relations such as these in
>> manipulation of expressions.
>>
>> Thanks,
>> Sune
>>
>>
>
>

```

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