Re: Finding branches where general solution is possible
- To: mathgroup at smc.vnet.net
- Subject: [mg131943] Re: Finding branches where general solution is possible
- From: Narasimham <mathma18 at gmail.com>
- Date: Mon, 4 Nov 2013 23:17:39 -0500 (EST)
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..... > > > > Setting si=x and si' = v > > > > v' /((1 + v) (1 + 2 v)) = Cot[x] > > > Integrate[1/((1 + v) (2 + v)), v] == > Integrate[Cot[x], x] > > Integrate[1/((1 + v) (2 + v)), v] == > Integrate[Cot[x]/v, x] > > Regards > Narasimham Further on, by hand calculation.. Integrate[v/((1 + v) (2 + v)), v] == Integrate[Cot[x], x] (1+v)/sqrt(1+ 2 v) = sin[si[t]]*const. q = (1+vi)/sqrt(1+ 2 vi),constant at boundary si=Pi/2. Let P = P[t]= q sin[si]; si'[th]= (P^2-1)+ P Sqrt[P^2-1] may be difficult to get general solution this way it appears. Does Mathematica have a work around for this? Regards Narasimham