[Date Index]
[Thread Index]
[Author Index]
Re: ListPlot - assigning a list of colors to a set of
*To*: mathgroup at smc.vnet.net
*Subject*: [mg131952] Re: ListPlot - assigning a list of colors to a set of
*From*: Gordon Robertson <grobertson at bcgsc.ca>
*Date*: Wed, 6 Nov 2013 00:34:23 -0500 (EST)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*Delivered-to*: l-mathgroup@wolfram.com
*Delivered-to*: mathgroup-outx@smc.vnet.net
*Delivered-to*: mathgroup-newsendx@smc.vnet.net
*References*: <20131105041619.448C769FC@smc.vnet.net>
Thank you.
For the immediate problem, yesterday I generated separate ListPlots for each label and combined the plots with Show, as David Park and Tomas Garza suggested. For future work, your approach should let me quickly assess what story a data table may offer.
nbr = 1000
xy = Transpose[{RandomReal[{0, 1}, nbr], RandomReal[{0, 1}, nbr]}];
cols = RandomChoice[{Red, Green, Blue}, nbr];
ListPlot[
List /@ xy,
PlotStyle -> (Directive[PointSize[0.02], Opacity[0.6], #] & /@
cols)]
Gordon
On 2013-11-05, at 11:59 AM, Bob Hanlon wrote:
There is no need to use Table with RandomChoice. Use
cols = RandomChoice[{Red, Green, Blue}, nbr]
Bob Hanlon
On Tue, Nov 5, 2013 at 12:12 PM, Gordon Robertson <grobertson at bcgsc.ca<mailto:grobertson at bcgsc.ca>> wrote:
Thanks Bob,
Your solutions are compact. The code below extends your first example to use a long list of XY coordinates and colours in ListPlot.
nbr = 1000
xy = Transpose[{RandomReal[{0, 1}, nbr], RandomReal[{0, 1}, nbr]}]; (* xy data to plot *)
cols = Table[RandomChoice[{Red, Green, Blue}], {i, nbr}]; (* list of colors *)
ListPlot[List /@ xy, PlotStyle -> (Directive[PointSize[0.02], Opacity[0.6], #] & /@ cols)]
Gordon
On 2013-11-05, at 8:34 AM, Bob Hanlon wrote:
Make each point a separate data list and repeat the PointSize:
ListPlot[List /@ {{1, 1}, {2, 2}, {3, 3}},
PlotStyle -> (Directive[PointSize[0.02], #] & /@
{Red, Green, Blue})]
Although you can use a List instead of Directive:
ListPlot[List /@ {{1, 1}, {2, 2}, {3, 3}},
PlotStyle -> ({PointSize[0.02], #} & /@
{Red, Green, Blue})]
Alternatively,
ListPlot[List /@ {{1, 1}, {2, 2}, {3, 3}},
PlotStyle -> {Red, Green, Blue},
PlotMarkers -> {Automatic, Medium}]
Bob Hanlon
On Mon, Nov 4, 2013 at 11:16 PM, Gordon Robertson <grobertson at bcgsc.ca<mail to:grobertson at bcgsc.ca>> wrote:
I'm using Mathematica v9.x on a Mac, with OS X 10.7.5.
Could I ask about something that likely has a very simple solution? I have a list of XY coordinates for say 500 points that will become a scatterplot via ListPlot. I need to assign a colour to each point, using a list of labels (histology, risk, =85).
I've generated ArrayPlot graphics for cases like this for some time. For example, given some labels in column 4 of a 'hist' table:
colours = Table[{
Switch[name = hist[[i, 4]],
"Classical", Green, "Tall cell", Red, "Other", Blue]
}, {i, Length[hist]}];
ArrayPlot[{colours}, AspectRatio -> 0.1, Frame -> False]
For a ListPlot, I'd have thought that something as simple as dropping a list of colours into a PlotStyle Directive would do the job. But the following line plots three blue points, rather than a Red, Green and Blue point.
ListPlot[{{1, 1}, {2, 2}, {3, 3}},
PlotStyle -> Directive[PointSize[0.02], {Red, Green, Blue}]]
Is there a simple way to declare a list of colours in ListPlot? I've looked through the PlotStyle documentation, and apologize if I've missed seeing how to do this.
Thanks very much for your help.
Gordon
--
Gordon Robertson
Michael Smith Genome Sciences Centre
BC Cancer Agency
Vancouver BC Canada
www.bcgsc.ca<http://www.bcgsc.ca/><http://www.bcgsc.ca<http://www.bcgsc.ca/>>
Prev by Date:
**Re: ListPlot - assigning a list of colors to a set of points**
Next by Date:
**Re: ListPlot - assigning a list of colors to a set of**
Previous by thread:
**Re: ListPlot - assigning a list of colors to a set of points**
Next by thread:
**Re: ListPlot - assigning a list of colors to a set of**
| |