Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2014

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Better way to test the number of arguments?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg132647] Re: Better way to test the number of arguments?
  • From: Pavel Grinfeld <pgeipi10 at gmail.com>
  • Date: Sun, 27 Apr 2014 21:45:04 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • Delivered-to: l-mathgroup@wolfram.com
  • Delivered-to: mathgroup-outx@smc.vnet.net
  • Delivered-to: mathgroup-newsendx@smc.vnet.net
  • References: <20140427064225.DB5346A1C@smc.vnet.net>

Thank you, Bob.
There's one difference in the output. If "f" is a vector(or tensor)-valued
function, I would like the new dimension to be first. For example if f is a
4x5 matrix and a function 1+7 variables, I would like the output to be
7x4x5.

How does one accomplish that?

Thanks again,

Pavel


On Sun, Apr 27, 2014 at 9:04 AM, Bob Hanlon <hanlonr357 at gmail.com> wrote:

> CORRECTION
>
> I left off there blank on the function:
>
> ddSaPartial[f_][args__]  := D[f[args],  {Rest@{args}}]
>
>
> 2014-04-27 8:56 GMT-04:00 Bob Hanlon <hanlonr357 at gmail.com>:
>
> ddSaPartial[f][args__]  := D[f[args],  {Rest@{args}}]
>>
>>
>>
>> Bob Hanlon
>>
>>
>> 2014-04-27 2:42 GMT-04:00 <pgeipi10 at gmail.com>:
>>
>> Hi,
>>>
>>> I have the following code that produces the gradient of a function (with
>>> respect to all but the first variable). There is probably a better way that
>>> avoids the Switch.
>>>
>>> Thank you,
>>>
>>> Pavel
>>>
>>> ddSaPartial[func_][t_, s__] := Switch[Length[{s}],
>>>   1, {Derivative[0, 1][func][t, s]},
>>>   2, {Derivative[0, 1, 0][func][t, s],
>>>    Derivative[0, 0, 1][func][t, s]},
>>>   3, {Derivative[0, 1, 0, 0][func][t, s],
>>>    Derivative[0, 0, 1, 0][func][t, s],
>>>    Derivative[0, 0, 0, 1][func][t, s]},
>>>   4, {Derivative[0, 1, 0, 0, 0][func][t, s],
>>>    Derivative[0, 0, 1, 0, 0][func][t, s],
>>>    Derivative[0, 0, 0, 1, 0][func][t, s],
>>>    Derivative[0, 0, 0, 0, 1][func][t, s]},
>>>   5, {Derivative[0, 1, 0, 0, 0, 0][func][t, s],
>>>    Derivative[0, 0, 1, 0, 0, 0][func][t, s],
>>>    Derivative[0, 0, 0, 1, 0, 0][func][t, s],
>>>    Derivative[0, 0, 0, 0, 1, 0][func][t, s],
>>>    Derivative[0, 0, 0, 0, 0, 1][func][t, s]}
>>>
>>>
>>>
>>>
>>
>



  • Prev by Date: Inverse function solution
  • Next by Date: Re: Function parameterization guess
  • Previous by thread: Re: Better way to test the number of arguments?
  • Next by thread: Re: Better way to test the number of arguments?