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BSplineSurface & BSplineFunction_Extracting Data

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  • Subject: [mg132223] BSplineSurface & BSplineFunction_Extracting Data
  • From: Bill <WDWNORWALK at aol.com>
  • Date: Mon, 20 Jan 2014 04:00:05 -0500 (EST)
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Hi:

I have the following Mathematica 8.0.4. code which plots the following:

In[1]:=  cpts={{{1,1,-0.5740579178735179`},{1,2,0.3902669640296943`},{1,3,0.6162142022057271`},{1,4,-0.11572153782589911`},{1,5,0.436662579150056`}},{{2,1,0.8096824307907462`},{2,2,-0.7419265507701529`},{2,3,-0.8659156744537175`},{2,4,-0.0998628811371658`},{2,5,-0.24185346526195106`}},{{3,1,-0.1969086942688163`},{3,2,0.7961076758026819`},{3,3,-0.060290070096196136`},{3,4,0.48665856202059254`},{3,5,-0.013419247141178037`}},{{4,1,0.6573342854316904`},{4,2,-0.9170657725998455`},{4,3,0.9830103505987027`},{4,4,-0.8759376369982923`},{4,5,-0.03030297194593956`}},{{5,1,-0.549653902873303`},{5,2,0.7865815336945703`},{5,3,-0.6672322036832838`},{5,4,0.5688838564868042`},{5,5,0.5541079809436917`}}};
surf1=Graphics3D[BSplineSurface[cpts]];

(*Plot omitted.*)

I then used the following code to extract data:  Note "Automatic" at the end in Out[4].

In[3]:=  f=BSplineFunction[cpts]

Out[3]=  BSplineFunction[{{0.,1.},{0.,1.}},<>]

In[4]:= f[[5]],f[[6]]

Out[4]= {{{{1.,1.,-0.574058},{1.,2.,0.390267},{1.,3.,0.616214},{1.,4.,-0.115722},{1.,5.,0.436663}},{{2.,1.,0.809682},{2.,2.,-0.741927},{2.,3.,-0.865916},{2.,4.,-0.0998629},{2.,5.,-0.241853}},{{3.,1.,-0.196909},{3.,2.,0.796108},{3.,3.,-0.0602901},{3.,4.,0.486659},{3.,5.,-0.0134192}},{{4.,1.,0.657334},{4.,2.,-0.917066},{4.,3.,0.98301},{4.,4.,-0.875938},{4.,5.,-0.030303}},{{5.,1.,-0.549654},{5.,2.,0.786582},{5.,3.,-0.667232},{5.,4.,0.568884},{5.,5.,0.554108}}},Automatic}

Out[5]= 
{{0.,0.,0.,0.,0.5,1.,1.,1.,1.},{0.,0.,0.,0.,0.5,1.,1.,1.,1.}}

In[6]:= {uk,vk}=%;

In[7]:=surf2=Graphics3D[{BSplineSurface[cpts,SplineKnots->{uk,vk},SplineDegree->3,SplineWeights ->Automatic];

(*Plot omitted.*)

Question:  Is there some way to extract the SplineWeights values that Mathematica used for "SplineWeights ->Automatic"?


Thanks,

Bill W.



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