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Original Message (ID '193279') By yehuda:
In Response To 'Re: Re: Re: Polynomial factorization by roots?' --------- Well, this is a Mathematica forum rather than a forum glorying HP50G and alike Another solution which is general but shorter than my previous answer is p = x^4 + 2 x^2 + 1; Factor[p, Extension -> (x /. Solve[p == 0, x])] Another example p1 = x^3 - 3*x^2 - 2*x + 6; Factor[p1, Extension -> (x /. Solve[p1 == 0, x])] so this is soluble in one short line of Mathematica yehdua