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Student Support Forum > General > > "b=a+1, c=b+1, d=c+1... x=?"

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Please answer this:3+1 =



Original Message (ID '198458') By Bill Simpson:
In[1]:= RSolve[{y[0]==4,y[x]==y[x-1]+1},y[x],x] Out[1]= {{y[x]->4+x}} This also works for some more complicated recurrence relations.