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Please answer this:1+1 =



Original Message (ID '467202') By Bill Simpson:
If you give n a fixed integer value then this is possible. In[1]:= n = 6; Expand[Sum[Pochhammer[1, -1 + k] Sum[(-1)^m Binomial[k, m] b[-m + n], {m, 0, k}]/k!, {k, 1, n}]] Out[2]= b[0]/6 - (6*b[1])/5 + (15*b[2])/4 - (20*b[3])/3 + (15*b[4])/2 - 6*b[5] + (49*b[6])/20 Without a fixed integer value I don't believe anything can be done.