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Please answer this:1+2 =

Original Message (ID '74424') By Peter Pein:
Hi, Bill's solution works of course but i guess you wanted to know why your attempt did not. In[1]:= f = 3 x Out[1]= 3 x In[2]:= Function[x, f][Pi] Out[2]= 3 x does not work because Function does not evaluate its arguments: In[3]:= Attributes[Function] Out[3]= {HoldAll, Protected} In[4]:= Function[x, Evaluate[f]][Pi] Out[4]= 3 Pi does what you expect. Peter