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 Author Comment/Response yehuda ben-shimol 10/31/06 08:00am Hi, I just Noticed that 1/Cos[x] is represented as Sec[x] so Sin[qi]^2 + 4/Cos[qi] - 1 /. {Sin[qi] -> qi, 1/Cos[qi] -> 1} As a general approach you may also consider using the series expansion as Sin[x]^2 + 4/Cos[x] - 1 /. {Sin[q_] -> Normal[Series[Sin[q], {q, 0, 1}]], Sec[ q_] -> Normal[Series[Sec[q], {q, 0, 1}]]} regards yehuda URL: ,

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