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Author Comment/Response
yehuda ben-shimol
10/31/06 08:00am

Hi,
I just Noticed that 1/Cos[x] is represented as Sec[x]
so
Sin[qi]^2 + 4/Cos[qi] - 1 /. {Sin[qi] -> qi, 1/Cos[qi] -> 1}

As a general approach you may also consider using the series expansion as

Sin[x]^2 + 4/Cos[x] - 1 /. {Sin[q_] ->
Normal[Series[Sin[q], {q, 0, 1}]], Sec[
q_] -> Normal[Series[Sec[q], {q, 0, 1}]]}

regards
yehuda

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Subject (listing for 'Linearization')
Author Date Posted
Linearization Serafin 10/30/06 03:00am
Re: Linearization yehuda ben-s... 10/31/06 07:31am
Re: Linearization - correction yehuda ben-s... 10/31/06 08:00am
Re: Linearization - a more general solution yehuda ben-s... 10/31/06 11:57pm
Re: Linearization Serafin 11/02/06 04:24am
Re: Linearization yehuda ben-s... 11/03/06 10:42pm
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