| Author |
Comment/Response |
yehuda ben-shimol
|
 10/31/06 08:00am
Hi,
I just Noticed that 1/Cos[x] is represented as Sec[x]
so
Sin[qi]^2 + 4/Cos[qi] - 1 /. {Sin[qi] -> qi, 1/Cos[qi] -> 1}
As a general approach you may also consider using the series expansion as
Sin[x]^2 + 4/Cos[x] - 1 /. {Sin[q_] ->
Normal[Series[Sin[q], {q, 0, 1}]], Sec[
q_] -> Normal[Series[Sec[q], {q, 0, 1}]]}
regards
yehuda
URL: , |
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