| Author |
Comment/Response |
yehuda ben-shimol
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 10/31/06 11:57pm
Well, it seems that the jet lag is effecting me stronger than I imagined
Here is a yet better solution which will approximate all functions of x near the origin to the first order. No explicit preknowledge of the functions involved is required, and it eliminates also the knowledge that Mathematica represents 1/Cos[x] as Sec[x] etc.
Sin[x]^2 + 4/Cos[x] - 1 /. fun_[q_] -> Normal[Series[fun[q], {q, 0, 1}]]
yehuda
URL: , |
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