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Student Support Forum: 'Divide doesn't evaluate' topicStudent Support Forum > General > "Divide doesn't evaluate"

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Author Comment/Response
Peter Pein
 10/06/07 10:12am

Hello Humphrey,

have a look at

In[1]:=
FullForm[a/b]

Out[1]//FullForm=
Times[a, Power[b, -1]]

so you have to define the reciprocal of your datatype

DateSeries /: Power[b_DateSeries,-1]:=...

Regards,
Peter

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Subject (listing for 'Divide doesn't evaluate')
Author Date Posted
Divide doesn't evaluate Humphrey 09/20/07 07:22am
Re: Divide doesn't evaluate Peter Pein 10/06/07 10:12am
Re: Re: Divide doesn't evaluate Humphrey Dru... 10/09/07 5:40pm
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