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 Author Comment/Response Bill 12/16/12 10:52pm Hi: This isn't exactly what you asked for, but perhaps it may be helpful... Using NMinimize, solve this problem: Find the point P on the plane -2 x + 1 y + 3 z = -3 closest to the point Q(5,0,-7) and the distance between these two points. NMinimize[{(x - 5)^2 + y^2 + (z + 7)^2, -2 x + 1 y + 3 z == -3}, {x, y, z}] Out: {56., {x -> 1., y -> 2., z -> -1.}} distance = Sqrt[56] // N Out: 7.48331 Hth, Bill URL: ,

 Subject (listing for 'Calculating point-plane distance') Author Date Posted Calculating point-plane distance Jules 12/14/12 10:35pm Re: Calculating point-plane distance Bill Simpson 12/16/12 5:12pm Re: Re: Calculating point-plane distance Jules 12/16/12 6:52pm Re: Re: Re: Calculating point-plane distance Bill Simpson 12/16/12 11:30pm Re: Calculating point-plane distance Bill 12/16/12 10:52pm
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