| Author |
Comment/Response |
RKTCD
|
 12/20/12 05:58am
Hi,
I have a distribution for my angles, and I can plot the distribution however I want a plot that shows the true distribution taking into account the fact that zero and 2pi are the same angle etc.
distriFunc[x_] := E^(-((-\[Pi] + x)^2/(18 \[Pi]^2)))/(
3 Sqrt[2] \[Pi]^(3/2))
Plot[E^(-((-\[Pi] + x)^2/(18 \[Pi]^2)))/(
3 Sqrt[2] \[Pi]^(3/2)), {x, -8 Pi, 9 Pi}]
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