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Jeff
09/23/08 11:55am

I have 3 points which I've graphed, where if they're connected they generate a plane.

ListPlot3D[{{1, 3, -2}, {3, 4, 2}, {1, -1, 0}}, Mesh -> All,
AxesLabel -> {x, y, z}]

I crossed 2 vectors to form a vector normal to the plane, and used the direction numbers to find an equation of the plane:

Cross[{2, 1, 4}, {-2, 3, -2}]
{-14, -4, 8}

So now with the direction numbers and using point (3,4,2)

-12(x - 3) - 4(y - 4) + 8(z - 2) = 0

= -12x + 36 - 4y +16 +8z -16 = 0
= -12x -4y +8z = -36

.... dividing by 4 on both sides

-3x - y +2z = -9 so this is the equation of the plane.

How can I verify graphically that the plane I derived with the equation, is the plane in my original plot?

Thanks,

Jeff

Attachment: p42 Lesson 11.5.nb, URL: ,

Subject (listing for 'Graphing a Plane')
Author Date Posted
Graphing a Plane Jeff 09/23/08 11:55am
Re: Graphing a Plane Bill 09/23/08 2:20pm
Re: Re: Graphing a Plane Jeff 09/23/08 8:44pm
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