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 Author Comment/Response Steve Keeley 12/28/12 12:11pm In Response To 'Re: Re: Polynomial factorization by roots?'---------I haven't played with it much, so I really can't say. Check the documentation under the "Factor" command. It seems you have to know what term you want in the factor, in this case "i". The example given uses it to get Sqrt[2] to show up in the factorization. "Factor" assumes that all coefficients in the factors are rational numbers. with "Extension" you can extend the types of factors it will produce. (You can use the "Roots" function to find the factor you're looking for.) URL: ,

 Subject (listing for 'Polynomial factorization by roots?') Author Date Posted Polynomial factorization by roots? Gandalf Saxe 12/11/12 11:08am Re: Polynomial factorization by roots? Nasser M. Ab... 12/12/12 08:07am Re: Polynomial factorization by roots? Gandalf 12/18/12 08:58am Re: Polynomial factorization by roots? Steve Keeley 12/25/12 7:44pm Re: Re: Polynomial factorization by roots? Steve Keeley 12/26/12 7:30pm Re: Polynomial factorization by roots? Steve Keeley 12/26/12 7:48pm Re: Re: Polynomial factorization by roots? Gandalf Saxe 12/28/12 05:36am Re: Re: Re: Polynomial factorization by roots? yehuda 12/28/12 11:39am Re: Re: Re: Polynomial factorization by roots? Steve Keeley 12/28/12 12:11pm Re: Re: Re: Polynomial factorization by roots? Steve Keeley 12/28/12 1:02pm Re: Re: Re: Re: Polynomial factorization by roo... yehuda 12/29/12 00:17am
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