| Author |
Comment/Response |
Xavier
|
 09/28/08 1:58pm
Hey,
To do so, you must unprotect Log to create a new definition. You must also write a thing like:
Unprotect[Log];
Log[0]=0;
Protect[Log];
I would indeed advice you to reprotect Log afterwards to avoid conflicts with new definitions you might create.
Cheers,
Xavier
URL: http://zavou.zxr.fr, |
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