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Xavier
09/28/08 2:08pm

Hey,

I am not quite sure I got you: the roots of your polynom is
{{n -> 1/3 (-3 - I Sqrt[3])}, {n ->
1/3 (-3 + I Sqrt[3])}}
that is two solutions, so K equates that. So why would you make a table of K with the index n?

Isn't K the value of n so that your polynom equates zero? If not, I guess I may need some more explanations about your
"Expression: Root of 3n^2+6*n+4"
to then help you. Sorry.
Cheers,

Xavier

URL: http://zavou.zxr.fr,

Subject (listing for 'IntegerQ')
Author Date Posted
IntegerQ Ann 09/27/08 12:41pm
Re: IntegerQ Xavier 09/28/08 2:08pm
Re: IntegerQ Tom 09/29/08 07:12am
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