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 Author Comment/Response yehuda 12/29/12 00:17am In Response To 'Re: Re: Re: Polynomial factorization by roots?'---------Well, this is a Mathematica forum rather than a forum glorying HP50G and alike Another solution which is general but shorter than my previous answer is p = x^4 + 2 x^2 + 1; Factor[p, Extension -> (x /. Solve[p == 0, x])] Another example p1 = x^3 - 3*x^2 - 2*x + 6; Factor[p1, Extension -> (x /. Solve[p1 == 0, x])] so this is soluble in one short line of Mathematica yehdua URL: ,

 Subject (listing for 'Polynomial factorization by roots?') Author Date Posted Polynomial factorization by roots? Gandalf Saxe 12/11/12 11:08am Re: Polynomial factorization by roots? Nasser M. Ab... 12/12/12 08:07am Re: Polynomial factorization by roots? Gandalf 12/18/12 08:58am Re: Polynomial factorization by roots? Steve Keeley 12/25/12 7:44pm Re: Re: Polynomial factorization by roots? Steve Keeley 12/26/12 7:30pm Re: Polynomial factorization by roots? Steve Keeley 12/26/12 7:48pm Re: Re: Polynomial factorization by roots? Gandalf Saxe 12/28/12 05:36am Re: Re: Re: Polynomial factorization by roots? yehuda 12/28/12 11:39am Re: Re: Re: Polynomial factorization by roots? Steve Keeley 12/28/12 12:11pm Re: Re: Re: Polynomial factorization by roots? Steve Keeley 12/28/12 1:02pm Re: Re: Re: Re: Polynomial factorization by roo... yehuda 12/29/12 00:17am
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