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Student Support Forum: 'Continuous Function and 2D image !' topicStudent Support Forum > General > "Continuous Function and 2D image !"

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Ram
11/23/08 2:04pm

Hi Mathematica Guru's,

I am stuck with a problem in evaluating a continous function. I have two images (A and B), out of which ImageB is interpolated with a continuous function (ListInterpolation).
I want to replace the intensity values of ImageA only when it finds a solution to the equation.
I have NO idea how to get a solution to this equation. So please I ask for experts in the field to help me !!


Two Images:
ImageA = Import["image1.tiff];
ImageB = Import["image2.tiff];

Interpolation of image B:
ImageFunction = ListInterpolation[Transpose[ImageB]];

Length of the image:
Xvalues = Table[a, {a, 1, Length[ImageA]}];
Yvalues = Table[b, {b, 1, Length[ImageA[[2]]]}];

(* Here is the confusion should I use Nsolve or evaluate for an equation ?? so that when it is 'true' it should change ImageA[[i,j]]=0 otherwise ImageA[[i,j]]=1.

I tried in this way!! and Ofcouse there is something wrong in it*)

Replacement:
For[i = 1, i ≤ Length[Xvalues],
For[j = 1, j ≤ Length[Yvalues],
Test[i,j] = If[Evaluate[(i-ImageFunction[x])^2 +
(j - ImageFunction[y])^2 + (ImageA[[i,j]]-ImageFunction[x][y])^2] <= 1, ImageA[[i,j]]=0,ImageA[[i,j]]=1];j++];i++];

It should evalute (when i = 1 for all continuous x-values of imageB, when j = 1 for all continuous y-values of imageB and differene in pixel value of imageA[1,1] and all continuous pixel values of imageB) <= 1.

Finally display the image:
ListDensityPlot[ImageA[[All, All]], Mesh -> False];

Is it not working because of the continuous function or my approach is wrong or should i use some other function instead of evaluate or the syntax problem??

Thanks for your help inadvance !!

Ram



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Author Date Posted
Continuous Function and 2D image ! Ram 11/23/08 2:04pm
Re: Continuous Function and 2D image ! Xavier 12/30/08 06:18am
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