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 Author Comment/Response Ram 11/23/08 2:04pm Hi Mathematica Guru's, I am stuck with a problem in evaluating a continous function. I have two images (A and B), out of which ImageB is interpolated with a continuous function (ListInterpolation). I want to replace the intensity values of ImageA only when it finds a solution to the equation. I have NO idea how to get a solution to this equation. So please I ask for experts in the field to help me !! Two Images: ImageA = Import["image1.tiff]; ImageB = Import["image2.tiff]; Interpolation of image B: ImageFunction = ListInterpolation[Transpose[ImageB]]; Length of the image: Xvalues = Table[a, {a, 1, Length[ImageA]}]; Yvalues = Table[b, {b, 1, Length[ImageA[[2]]]}]; (* Here is the confusion should I use Nsolve or evaluate for an equation ?? so that when it is 'true' it should change ImageA[[i,j]]=0 otherwise ImageA[[i,j]]=1. I tried in this way!! and Ofcouse there is something wrong in it*) Replacement: For[i = 1, i ≤ Length[Xvalues], For[j = 1, j ≤ Length[Yvalues], Test[i,j] = If[Evaluate[(i-ImageFunction[x])^2 + (j - ImageFunction[y])^2 + (ImageA[[i,j]]-ImageFunction[x][y])^2] <= 1, ImageA[[i,j]]=0,ImageA[[i,j]]=1];j++];i++]; It should evalute (when i = 1 for all continuous x-values of imageB, when j = 1 for all continuous y-values of imageB and differene in pixel value of imageA[1,1] and all continuous pixel values of imageB) <= 1. Finally display the image: ListDensityPlot[ImageA[[All, All]], Mesh -> False]; Is it not working because of the continuous function or my approach is wrong or should i use some other function instead of evaluate or the syntax problem?? Thanks for your help inadvance !! Ram URL: ,

 Subject (listing for 'Continuous Function and 2D image !') Author Date Posted Continuous Function and 2D image ! Ram 11/23/08 2:04pm Re: Continuous Function and 2D image ! Xavier 12/30/08 06:18am
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