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Student Support Forum: 'b=a+1, c=b+1, d=c+1... x=?' topicStudent Support Forum > General > "b=a+1, c=b+1, d=c+1... x=?"

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Author Comment/Response
Steve Keeley
01/01/13 3:47pm

If I'm understanding correctly what you're trying to do, the simplest way would be:

y[n_] := 4 + n

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Subject (listing for 'b=a+1, c=b+1, d=c+1... x=?')
Author Date Posted
b=a+1, c=b+1, d=c+1... x=? Humperdinck ... 12/31/12 10:03pm
Re: b=a+1, c=b+1, d=c+1... x=? Steve Keeley 01/01/13 3:47pm
Re: b=a+1, c=b+1, d=c+1... x=? jf 01/01/13 3:55pm
Re: b=a+1, c=b+1, d=c+1... x=? Bill Simpson 01/01/13 6:58pm
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