| Author |
Comment/Response |
Casey Mann
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 12/21/98 12:53pm
Let x and y be two complex numbers, and let T[t_]:=tx+(1-t)y for t a real number be the line passing through x and y.
If I try this:
Solve[Abs[T[t]]]==1,t]
Solve will give the solution for t as a complex number, not a real number as I desire. How can I specify to Mathematica that I want t to be viewed as a real number.
Now, of course I was able to write my own command that solved the above equation by using conjugation (z*Conjugate[z]==Abs[z]^2), but I was using this example because it is relatively simple.
The equation that I'm really interested in solving is
Solve[Abs[Log[((x-y)(b-a))/((x-a)(b-y))]]==Abs[Log[((y-T[t])(b-a))/((y-a)(b-T[t]))]],t]
The solver will give solutions for t, but the are complex! I want t to be a real value. If only I could tell Mathematica that t is a real number. . .
Any help on this will be much appreciated.
Casey Mann
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