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Student Support Forum: 'b=a+1, c=b+1, d=c+1... x=?' topicStudent Support Forum > General > "b=a+1, c=b+1, d=c+1... x=?"

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Author Comment/Response
Bill Simpson
01/01/13 6:58pm

In[1]:= RSolve[{y[0]==4,y[x]==y[x-1]+1},y[x],x]

Out[1]= {{y[x]->4+x}}

This also works for some more complicated recurrence relations.

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Subject (listing for 'b=a+1, c=b+1, d=c+1... x=?')
Author Date Posted
b=a+1, c=b+1, d=c+1... x=? Humperdinck ... 12/31/12 10:03pm
Re: b=a+1, c=b+1, d=c+1... x=? Steve Keeley 01/01/13 3:47pm
Re: b=a+1, c=b+1, d=c+1... x=? jf 01/01/13 3:55pm
Re: b=a+1, c=b+1, d=c+1... x=? Bill Simpson 01/01/13 6:58pm
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