Student Support Forum: 'b=a+1, c=b+1, d=c+1... x=?' topicStudent Support Forum > General > "b=a+1, c=b+1, d=c+1... x=?"
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Comment/Response |
Bill Simpson
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 01/01/13 6:58pm
In[1]:= RSolve[{y[0]==4,y[x]==y[x-1]+1},y[x],x]
Out[1]= {{y[x]->4+x}}
This also works for some more complicated recurrence relations.
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Subject (listing for 'b=a+1, c=b+1, d=c+1... x=?')
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Author |
Date Posted
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 b=a+1, c=b+1, d=c+1... x=? |
Humperdinck ... |
12/31/12 10:03pm |
 Re: b=a+1, c=b+1, d=c+1... x=? |
Steve Keeley |
01/01/13 3:47pm |
| Re: b=a+1, c=b+1, d=c+1... x=? |
jf |
01/01/13 3:55pm |
 Re: b=a+1, c=b+1, d=c+1... x=? |
Bill Simpson |
01/01/13 6:58pm |
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