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I am completely new to this so please forgive me if this ? has been asked before (I searched but couldn't find the answer to my ?).
How can I use Mathematica to solve the following:
If x is normally distributed with mean = 25.0 and a standard deviation = 5, how can I determine the following
P(x is greater than or equal to 25.0)
I tried using the PDF[NormalDistribution[\[Mu], \[Sigma]], x] function but it just returns the following:
E^(-(1/32) (-25 + (x > 25))^2)/(4 Sqrt[2 \[Pi]])
I know the answer is 0.5 but I want to know how I can go about calculating this using the program.