Author 
Comment/Response 
Elliot Schrock

05/30/09 11:31pm
Hi,
So, I'm trying to solve a series of equations that are apparently difficult for mathematica to process. First, I define a couple functions, with no problems:
k[t_] := Piecewise[{{6, 0 < t < 24}, {
0, 24 < t < 48}, {6, 48 < t < 72}, {
0, 72 < t < 96}, {3, 96 < t < 120}, {0, t > 120}}]
and
H[t_] := x[t] h[t]  k[t]h[t] + h[t]u[t] + l[t](24  k[t]  h[t]  u[t]).
Next, I ask Mathematica to solve several equations involving these functions for the functions of t contained in H:
DSolve[{D[H[t], h[t]] == 0,
D[H[t], u[t]] == 0,
D[H[t], x[t]] == l'[t], D[H[t], l[t]] == x'[t], x[0] ==
0, l[168] == 0}, {h[t], u[t], x[t], l[t]}, t].
This doesn't give me any problems, and outputs the solutions. However, the H defined above is a simplified version of the actual function I want to use. So, when I make H more complicated, say, like so:
H[t_] := x[t]^2 h[t]  k[t]h[t] + h[t]u[t] + l[t](24  k[t]  h[t]  u[t])
where all I've done is square the first x[t], Mathematica gives me the error:
Solve::svars: Equations may not give solutions for all "solve" variables.
The number of variables has not changed. Why am I getting that error?
When I try to instead add another variable to H, like so:
H[t_] := x[t]^(1/2) h[t]  k[t]h[t] + h[t]u[t] + l[t](24  k[t]  h[t]  u[t]  f[t])
where all that is added is an f[t], and then I run:
DSolve[{D[H[t], h[t]] == 0,
D[H[t], f[t]] == 0,
D[H[t], u[t]] == 0,
D[H[t], x[t]] == l'[t], D[H[t],
l[t]] == x'[t], x[0] == 0, l[168] == 0}, {h[t], u[
t], x[t], f[t], l[t]}, t]
where I've added the equation involving f and added it to the list of solve variables, I get no output at all, just the command I entered. When I both make it more complicated and add a variable, it gives me the svars error. What's going on? How can I fix it?
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