| Author |
Comment/Response |
VolMike
|
 01/08/13 03:44am
Look at s[n,x] - it is irrespective to n:
s[n,x]=f[x]= I(-Log[1 + E^(I x)] + Log[E^(-I x)(1 + E^(I x))]). Moreover, for -Pi<x<Pi s[n,x]==f[x]==x.
You can make a plot using this way:
f[x_] := Sum[((-1)^(n + 1)) (2/n) (Sin[n*x]), {n, 1, Infinity}]
Plot[f[x], {x, -3, 3}]
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