| Author |
Comment/Response |
David
|
 09/20/09 04:02am
I want to solve this:
x,y,z are natural numbers
x=y+3
x^2+y^2=z^2
x=?
I tried to do the following in mathematica:
list1 := Do[x^2, {x, 0, 5000, 1}]
list2 := Do[(x - 3)^2, {x, 0, 5000, 1}]
Intersection[(list1 + list2), list2]
The output is:
Intersection::normal: Nonatomic expression expected at position 2 in (2 Null)\[Intersection]Null. >>(2 Null) \[Intersection] Null
What do i do wrong?
URL: , |
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