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Author Comment/Response
yehuda ben-shimol
09/22/09 08:31am

I'm sure you already resolved this issue
but in any case use the function N
{{x -> -(1/3) + 25/(3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)) +
1/3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)}, {x -> -(1/3) -
1/6 (1 + I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - (
25 (1 - I Sqrt[3]))/(
3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}, {x -> -(1/3) -
1/6 (1 - I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - (
25 (1 + I Sqrt[3]))/(3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}} //N

or
N[{{x -> -(1/3) + 25/(3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)) +
1/3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)}, {x -> -(1/3) -
1/6 (1 + I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - (
25 (1 - I Sqrt[3]))/(
3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}, {x -> -(1/3) -
1/6 (1 - I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - (
25 (1 + I Sqrt[3]))/(3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}} ]

yehuda

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Subject (listing for 'Solving Polynomials')
Author Date Posted
Solving Polynomials Nick 09/19/09 4:58pm
Re: Solving Polynomials TomD 09/21/09 6:32pm
Re: Solving Polynomials yehuda ben-s... 09/22/09 08:31am
Re: Solving Polynomials Peter Pein 09/25/09 5:41pm
Re: Solving Polynomials Peter Pein 09/25/09 5:48pm
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