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 Author Comment/Response yehuda ben-shimol 09/22/09 08:31am I'm sure you already resolved this issue but in any case use the function N {{x -> -(1/3) + 25/(3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)) + 1/3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)}, {x -> -(1/3) - 1/6 (1 + I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - ( 25 (1 - I Sqrt[3]))/( 3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}, {x -> -(1/3) - 1/6 (1 - I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - ( 25 (1 + I Sqrt[3]))/(3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}} //N or N[{{x -> -(1/3) + 25/(3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)) + 1/3 (1/2 (-101 + 3 I Sqrt[5811]))^(1/3)}, {x -> -(1/3) - 1/6 (1 + I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - ( 25 (1 - I Sqrt[3]))/( 3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}, {x -> -(1/3) - 1/6 (1 - I Sqrt[3]) (1/2 (-101 + 3 I Sqrt[5811]))^(1/3) - ( 25 (1 + I Sqrt[3]))/(3 2^(2/3) (-101 + 3 I Sqrt[5811])^(1/3))}} ] yehuda URL: ,

 Subject (listing for 'Solving Polynomials') Author Date Posted Solving Polynomials Nick 09/19/09 4:58pm Re: Solving Polynomials TomD 09/21/09 6:32pm Re: Solving Polynomials yehuda ben-s... 09/22/09 08:31am Re: Solving Polynomials Peter Pein 09/25/09 5:41pm Re: Solving Polynomials Peter Pein 09/25/09 5:48pm
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