| Author |
Comment/Response |
Geuzt
|
 10/26/09 9:20pm
Is there any way to do this in Mathematica?
C = {1, 2, 3, 4, 5}
D = {r, s, t, l, n, e}.
C X D = {
(1, r), (1, s), (1, t), (1, l), (1, n), (1, e),
(2, r), (2, s), (2, t), (2, l), (2, n), (2, e),
(3, r), (3, s), (3, t), (3, l), (3, n), (3, e),
(4, r), (4, s), (4, t), (4, l), (4, n), (4, e),
(5, r), (5, s), (5, t), (5, l), (5, n), (5, e)
}
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