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Simplifying hyperbolic expr
01/16/10 4:06pm

I have an expression which is
(2*Cosh[r]^3-2*Sinh[r]^3-3*Cosh[r])/Sinh[r]^(3/2)

When I multiply this expression by 1/(Sinh(r))^(3/2) it reduces to a polynomial in Coth[r]

i.e.

3*Coth[r]-Coth[r]^3-2

Can you help me figure out how to make Mathematica realize this?

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Subject (listing for 'polynomials in Coth[r]')
Author Date Posted
polynomials in Coth[r] Simplifying ... 01/16/10 4:06pm
Re: polynomials in Coth[r] S. Saralamba 01/26/10 9:29pm
Re: Re: polynomials in Coth[r] Howard Cohl 01/27/10 2:23pm
Re: Re: Re: polynomials in Coth[r] Peter Pein 01/28/10 7:50pm
Re: polynomials in Coth[r] Peter Pein 01/28/10 8:19pm
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