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 Author Comment/Response Britnee Crawford 07/24/10 5:22pm Hi, I am trying to compute a triple integral with the inner integrals as variable limits of integration. NIntegrate doesn't seem to work because the limits are not numbers for the inner integrals. But, using Integrate takes forever and doesn't seem to run. I think part of the problem is that the function I am trying to integrate is piecewise with domain of each piece depending on a variable. Here is the syntax for the definition of the piecewise function: b0 := 0 b1 := 5 b2 := 50 b3 := 75 b4 := 100 b5 := Sqrt[(M5 (b4^2 - b3^2) + M4 b4^2)/M4] M1 := 0.51 M2 := 0 M3 := 0.0375 M4 := 0.0125 M5 := 0.44 r0[x_] := (b0 Sqrt[1 - e^2])/(1 - e Sin[x]) r1[x_] := (b1 Sqrt[1 - e^2])/(1 - e Sin[x]) r2[x_] := (b2 Sqrt[1 - e^2])/(1 - e Sin[x]) r3[x_] := (b3 Sqrt[1 - e^2])/(1 - e Sin[x]) r4[x_] := (b4 Sqrt[1 - e^2])/(1 - e Sin[x]) r5[x_] := (b5 Sqrt[1 - e^2])/(1 - e Sin[x]) f1[x_] := (M1 Sqrt[1 - e^2])/(Pi (b1^2 - b0^2)) f2[x_] := (M2 Sqrt[1 - e^2])/(Pi (b2^2 - b1^2)) f3[x_] := (M3 Sqrt[1 - e^2])/(Pi (b3^2 - b2^2)) f4[x_] := (M4 Sqrt[1 - e^2])/(Pi (b4^2 - b3^2)) f5[x_] := (M5 Sqrt[1 - e^2])/(Pi (b5^2 - b4^2)) Psi[r_, x_] := Piecewise[{{f1[x], r <= r1[x]}, {f2[x], r1[x] < r <= r2[x]}, {f3[x], r2[x] < r <= r3[x]}, {f4[x], r3[x] < r <= r4[x]}, {f5[x], r4[x] < r <= r5[x]}}] Then, here is the integral: N[Integrate[ Integrate[ Integrate[Psi[r, x] r, {r, r1[x], r5[x]}], {x, right[y], left[y]}], {y, -b5, 0}]] "right[y]" and "left[y]" are two functions of y that I have defined, but not written here. I have tried several different ways of writing this integral (using nested Integrate, or just 1 Integrate as a triple integral). Can anyone help? Britnee Crawford URL: ,

 Subject (listing for 'complicated triple integral') Author Date Posted complicated triple integral Britnee Craw... 07/24/10 5:22pm Re: complicated triple integral Peter Pein 08/01/10 05:38am Re: complicated triple integral yehuda ben-s... 08/01/10 12:46pm Re: complicated triple integral Britnee Craw... 08/09/10 2:07pm
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