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Student Support Forum: 'Reduce in v.6 and v.7' topicStudent Support Forum > General > Archives > "Reduce in v.6 and v.7"

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Author Comment/Response
Laura
08/16/10 3:18pm

I have been using Reduce on the following in version 6:

m1f1a := \[Alpha]L >= \[Alpha]H
m1f1b := (1 + dM (-1 + H))^z <= 1
m1f1c := 1 + 2 \[Alpha]L >= (1 + dM (-1 + H))^z + 2 \[Alpha]H

Reduce[m1f1a && m1f1b && m1f1c && \[Alpha]L > \[Alpha]H &&
0 < \[Alpha]L < 1/2 && 0 < \[Alpha]H < 1/2 && 0 <= dM <= 1 &&
H >= 2 && z > 0, Reals]

which gives me:

dM == 0 && H >= 2 && z > 0 &&
0 < \[Alpha]H < 1/2 && \[Alpha]H < \[Alpha]L < 1/2

However, when I do the same in version 7, I get:

Reduce::nsmet: This system cannot be solved with the methods available to Reduce. >>

According to the Help files, Reduce was last changed in version 5. Does anybody have any idea what may be going on?

Many thanks,
Laura

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Subject (listing for 'Reduce in v.6 and v.7')
Author Date Posted
Reduce in v.6 and v.7 Laura 08/16/10 3:18pm
Re: Reduce in v.6 and v.7 Onkar 08/25/10 10:36am
Re: Re: Reduce in v.6 and v.7 Onkar 08/25/10 1:49pm
Re: Re: Re: Reduce in v.6 and v.7 Laura 08/25/10 6:45pm
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