Author 
Comment/Response 
Fibonacci Prower

04/15/11 11:56pm
Given a sequence of abscissas t0 < t1 < ... < tn, I want a (actually, the unique) cubic spline S such that S(t0)=y0, ..., S(tn)=yn, and in addition, S'(t0)=k0, S'(tn)=k1.
First question: How can I obtain such a function in Mathematica?
Second question: Having obtained such a function, how can I see the explicit cubic polynomials of which it is composed?
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