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 Author Comment/Response Bill Simpson 01/20/13 8:31pm Turn each of your inequalities into an equality. Thus x+y<7 becomes x+y==7. For every pair of equalities use Solve to find the unique intersection. Thus {x,y}/.Solve[{3x+y==7, 2x-y==2}, {x,y}][[1]] The Outer[] function might help you do this. http://reference.wolfram.com/mathematica/ref/Outer.html?q=Outer&lang=en Use ConvexHull on the resulting set of points. http://reference.wolfram.com/mathematica/ComputationalGeometry/ref/ConvexHull.html You might try doing this one small step at a time, while verifying that each step gives a correct result, before trying everything at once. URL: ,

 Subject (listing for 'Vertices of a polygon defined by inequalities') Author Date Posted Vertices of a polygon defined by inequalities Vincenzo M 01/19/13 09:31am Re: Vertices of a polygon defined by inequalities Bill Simpson 01/20/13 8:31pm
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