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 Author Comment/Response Gandalf Saxe 11/30/11 06:26am Hi everyone. I've been using basically a whole day on two trivial Mathematica issues, so I'm finally going online for help: 1. Is there any simple way to define the gradient as a new function as such? My try: Clear["Global`*"] f[u_] := x[u]*y[u] gradf[u_] := D[f[u], {{x[u], y[u]}}] gradf[u] x[u_] := Exp[u] y[u] := Cos[u] gradf[u] Which gives: "General::ivar: E^u is not a valid variable. >>" I can kind of see what the problem is, but I don't know how to fix it. It works fine if I define gradf as an expression instead of a function (without the [u_]:), but I'd like it as a function. Any simple solution? 2. See the attachment. On the final line, it doesn't evaluate the function r2[0] properly. I think the problem is how h[u] is defined as h[u_]:= f[x,y], doesn't work apparently. Any suggestions? Also I'd love any general suggestions on how to do things easier or simpler in the notebook attachement. I'm a total beginner in Mathematica (just came from Maple) so I probably do a some things not the easiest or simplest way. Any feedback would be good Any help is appreciated. Thanks Attachment: Mat1P13a.nb, URL: ,

 Subject (listing for 'Trouble with defining function from gradiant') Author Date Posted Trouble with defining function from gradiant Gandalf Saxe 11/30/11 06:26am Re: Trouble with defining function from gradiant Quinn McKinsey 12/01/11 10:13pm Re: Re: Trouble with defining function from gra... Gandalf Saxe 12/02/11 2:56pm Re: Re: Trouble with defining function from gra... Gandalf Saxe 12/02/11 8:27pm
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