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Student Support Forum: 'Taylor expansion of 1/1-x' topicStudent Support Forum > General > Archives > "Taylor expansion of 1/1-x"

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Valerio
01/08/12 04:48am

Hello everybody! Excuse me for my possibly poor english but as you can guess from my name, I'm Italian. My question is kind of silly, but I'll submit it anyway because it puzzles me.

If i take f(x)=1/(1-x) and expand it using the Taylor formula, and 0 as centre, i obtain:

Tn(x,0)=1+x+x^2+x^3...+x^n

..That is the geometric series.

Now, if i calculate the value of the polynomial in x=-1, i'll obtain -of course- 1/2...but:

1/2 = 1-1+1-1+1-1+1....

??? I can't figure out the meaning of this!


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Subject (listing for 'Taylor expansion of 1/1-x')
Author Date Posted
Taylor expansion of 1/1-x Valerio 01/08/12 04:48am
Re: Taylor expansion of 1/1-x Nasser M. Ab... 01/08/12 4:08pm
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