Author 
Comment/Response 
Muneerah

04/27/12 4:46pm
I tried the following
f[n_] := ((3 n + 1)! (2 n  5)! )/( (n + 1)!)^2
Using FullSimplify[f[n1]/f[n]]
I got
(1 + n)^2/(6 n (15 + 11 n + 133 n^2  99 n^3 + 18 n^4))
which is fine (Mathematica simplified the factorial expression). However FullSimplify[f[n2]/f[n]] resulted in
(Gamma[2 + n]^2 Gamma[8 + 2 n] Gamma[4 + 3 n])/(
Gamma[n]^2 Gamma[4 + 2 n] Gamma[2 + 3 n])
The factorials were left in. Any ideas on how to get Mathematica to simplify this to a rational function?
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