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 Author Comment/Response Bill Simpson 05/01/12 12:05pm Since your Piecewise function appears to only be a unit step function, pull that step out into the bounds of integration. This then appears to integrate almost instantly. In[1]:= f[x_]:=Sin[x];q=1/E; Integrate[Integrate[x f'''[x],{x,0,Min[1/q,1+u-Floor[q]]}, Assumptions->q>0],{u,0,1/q}, Assumptions->q>0] Out[3]= E-Cos[1]-Cos[E]+E Cos[E]+2 Sin[1]-2 Sin[E]-E Sin[E] Be careful that you get the bounds of integration correct. If you can see how to get rid of that Min[] it would probably be even better. URL: ,

 Subject (listing for 'symbolic integral calculates infinitly long') Author Date Posted symbolic integral calculates infinitly long igor_igel 04/27/12 8:29pm Re: symbolic integral calculates infinitly long Bill Simpson 05/01/12 12:05pm Re: Re: symbolic integral calculates infinitly ... Peter Pein 05/02/12 03:09am
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