Mathematica 9 is now available
Student Support Forum
Student Support Forum: 'Abs of Complex fraction' topicStudent Support Forum > General > Archives > "Abs of Complex fraction"

Next Comment >Help | Reply To Topic
Author Comment/Response
05/04/12 1:57pm

Consider z = Cos[x] + I Sin[x].

If I take ComplexExpand[Abs[z]], the result is 1 (as it should).

But when I take ComplexExpand[Abs[1/z]], I get

1/Abs[Cos[x] + I Sin[x]].

Can anyone help? Why can't I get a valid expression?


URL: ,

Subject (listing for 'Abs of Complex fraction')
Author Date Posted
Abs of Complex fraction ND 05/04/12 1:57pm
Re: Abs of Complex fraction Max 05/27/12 8:38pm
Next Comment >Help | Reply To Topic