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Student Support Forum: 'Abs of Complex fraction' topicStudent Support Forum > General > "Abs of Complex fraction"

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ND
 05/04/12 1:57pm

Consider z = Cos[x] + I Sin[x].

If I take ComplexExpand[Abs[z]], the result is 1 (as it should).

But when I take ComplexExpand[Abs[1/z]], I get

1/Abs[Cos[x] + I Sin[x]].

Can anyone help? Why can't I get a valid expression?

Thanks.

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Subject (listing for 'Abs of Complex fraction')
Author Date Posted
Abs of Complex fraction ND 05/04/12 1:57pm
Re: Abs of Complex fraction Max 05/27/12 8:38pm
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