Student Support Forum: 'Abs[z] stays complex, z is constraint' topicStudent Support Forum > General > "Abs[z] stays complex, z is constraint"
| Author |
Comment/Response |
Max
|
 05/27/12 8:59pm
Hello everybody,
I got a problem and I`m new here!
I just downloaded Mathematica to get the Abs[] of a complex constraint. I started today with this program so Im a real greenhorn!
I wanted to get Abs[z]
butI dont get an expression. Just copied this out of the programm.
Abs[1/rf + (ri + x)/(lo^2 w^2 + (ri + x)^2) -
I (1/(lm^2 w^2) + (lo^2 w^2)/(lo^2 w^2 + (ri + x)^2))]
Thanks for your help!
Max
URL: , |
|
| | | |
| |
|
