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Student Support Forum: 'Abs[z] stays complex, z is constraint' topicStudent Support Forum > General > Archives > "Abs[z] stays complex, z is constraint"

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Max
05/27/12 8:59pm

Hello everybody,

I got a problem and I`m new here!


I just downloaded Mathematica to get the Abs[] of a complex constraint. I started today with this program so Im a real greenhorn!

I wanted to get Abs[z]

butI dont get an expression. Just copied this out of the programm.

Abs[1/rf + (ri + x)/(lo^2 w^2 + (ri + x)^2) -
I (1/(lm^2 w^2) + (lo^2 w^2)/(lo^2 w^2 + (ri + x)^2))]


Thanks for your help!
Max



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Subject (listing for 'Abs[z] stays complex, z is constraint')
Author Date Posted
Abs[z] stays complex, z is constraint Max 05/27/12 8:59pm
Re: Abs[z] stays complex, z is constraint jf 05/28/12 1:56pm
Re: Re: Abs[z] stays complex, z is constraint Max 05/28/12 2:52pm
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