| Author |
Comment/Response |
yehuda
|
 05/29/12 07:38am
First, Sum (as well as other iterator based functions such as Table, Do, etc.) handles multiple iterators, just replace their order
Sum[(2 (r1-1)) (2 (r2-1)-1) (2 (r3-1)-2) (2 (r4-1)-3),{r1,2,97},{r2,r1+1,98},{r3,r2+1,99},{r4,r3+1,100}]
as for your specific questions - replace Sum with Table and flatten it down to the third level
Flatten[Table[(2 (r1-1)) (2 (r2-1)-1) (2 (r3-1)-2) (2 (r4-1)-3),{r1,2,97},{r2,r1+1,98},{r3,r2+1,99},{r4,r3+1,100}],3]
yehuda
URL: , |
|
