| Author |
Comment/Response |
jf
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 06/21/12 10:50am
In Response To 'Re: Limit returns unevaluated input'
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If you move the Assuming outside, so Simplify sees it, too, the result is a little nicer.
In[1]:= Assuming[{b0>b1,b1>0,m0>m1,x\[Element]Reals&&n\[Element]Integers},Simplify[Limit[(2 \[Pi])^(-(1/2)) (((b0-b1) (b0+b1) (m0-m1) (-b1^2 (m0+m1 (-1+n)+3 m0 n-4 n x)+b0^2 (m0-m1+m0 n+3 m1 n-4 n x))+2 n (b1^2 (m0-x)+b0^2 (-m1+x))^2 (HarmonicNumber[(b0^2 n)/(b0^2-b1^2)]-HarmonicNumber[(b1^2 n)/(b0^2-b1^2)]))/(4 (b0-b1)^3 (b0+b1)^3)),n->Infinity]]]
Out[1]= DirectedInfinity[(b0^2-b1^2) (m0-m1) (-b1^2 (3 m0+m1-4 x)+b0^2 (m0+3 m1-4 x))+4 (b1^2 (m0-x)+b0^2 (-m1+x))^2 Log[b0] - 4 (b1^2 (m0-x)+b0^2 (-m1+x))^2 Log[b1]]
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